3n-18=-2n+4n^2

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Solution for 3n-18=-2n+4n^2 equation: 



3n-18=-2n+4n^2

We move all terms to the left:

3n-18-(-2n+4n^2)=0

We get rid of parentheses

-4n^2+2n+3n-18=0

We add all the numbers together, and all the variables

-4n^2+5n-18=0

a = -4; b = 5; c = -18;
Δ = b2-4ac
Δ = 52-4·(-4)·(-18)
Δ = -263
Delta is less than zero, so there is no solution for the equation

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